20q^2-41qb+20b^2=

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Solution for 20q^2-41qb+20b^2= equation: 


Simplifying
20q2 + -41qb + 20b2 = 0

Reorder the terms:
-41bq + 20b2 + 20q2 = 0

Solving
-41bq + 20b2 + 20q2 = 0

Solving for variable 'b'.

Factor a trinomial.
(4b + -5q)(5b + -4q) = 0


Subproblem 1
Set the factor '(4b + -5q)' equal to zero and attempt to solve:

Simplifying
4b + -5q = 0

Solving
4b + -5q = 0

Move all terms containing b to the left, all other terms to the right.

Add '5q' to each side of the equation.
4b + -5q + 5q = 0 + 5q

Combine like terms: -5q + 5q = 0
4b + 0 = 0 + 5q
4b = 0 + 5q
Remove the zero:
4b = 5q

Divide each side by '4'.
b = 1.25q

Simplifying
b = 1.25q

Subproblem 2
Set the factor '(5b + -4q)' equal to zero and attempt to solve:

Simplifying
5b + -4q = 0

Solving
5b + -4q = 0

Move all terms containing b to the left, all other terms to the right.

Add '4q' to each side of the equation.
5b + -4q + 4q = 0 + 4q

Combine like terms: -4q + 4q = 0
5b + 0 = 0 + 4q
5b = 0 + 4q
Remove the zero:
5b = 4q

Divide each side by '5'.
b = 0.8q

Simplifying
b = 0.8q
Solution
b = {1.25q, 0.8q}

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